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Using % in batch files Ok, I'm stumped here... I want to use a program in a batch file, but I need to pass it a parameter with a "%" in the name (like "%y"). What happens is that the %y gets expanded out into a variable, which is usually blank... hence I can't get my parameter to the program I'm trying to call! How can I escape the % to ensure that it gets sent as a %? AidanII
__________________ Any views, thoughts and opinions are entirely my own. They don't necessarily represent those of my employer (BlackBerry). |
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Flash of inspiration... Not /% Not \% But %% ![]() AidanII
__________________ Any views, thoughts and opinions are entirely my own. They don't necessarily represent those of my employer (BlackBerry). |
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